Post a New Question


posted by .

Two archers shoot arrows in the same direction from the same place with the same initial speeds, but at different angles. One shoots at 45.0degrees above the horizontal, while the other shoots at 60.0 degrees.If the arrow launched at 45.0 lands 225 from the archer, how far apart are the two arrows when they land? (You can assume that the arrows start at essentially ground level.)

  • Physics -

    (V^2/g)sin 90 = 225 m
    Solve for V. Note that sin 90 = 1.
    (Twice the launch angle appears in the formula)

    Then solve

    (V^2/g)(sin 90 - sin120) = X

    to get X, the distance between them.

  • Physics -

    thanks so much

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question