the mathematical relationship between velocity (v) and time (t) for a coin tossed up into the air after it leaves the thrower¡¦s hand at t = 0 with a velocity of +15.0 m/s. Assume that the positive direction is upward and the acceleration of the coin is ƒ{9.8 m/s2.
What is the question?
v(t)=15m/s - 9.8m/s^2 * t
Write down the mathematical relationship between velocity (v) and time (t) for a coin tossed up into the air after it leaves the thrower¡¦s hand at t = 0 with a velocity of +15.0 m/s. Assume that the positive direction is upward and the acceleration of the coin is ƒ{9.8 m/s2.
so I did it, right?
i think
so is my answer 0 for this?
To determine the mathematical relationship between velocity (v) and time (t) for a coin tossed up into the air, we need to consider the acceleration due to gravity and the initial velocity of the coin.
Given:
Initial velocity, u = +15.0 m/s (positive direction is upward)
Acceleration due to gravity, a = -9.8 m/s² (negative because it acts downward)
The relationship between velocity, initial velocity, acceleration, and time is given by the equation:
v = u + at
Substituting the given values:
v = 15.0 m/s + (-9.8 m/s²)t
Simplifying the equation, we have:
v = 15.0 - 9.8t m/s
So, the mathematical relationship between velocity (v) and time (t) for this coin tossed up into the air is:
v = 15.0 - 9.8t m/s