posted by Kathryn .
How many atoms of element "R" are present in 55.80 g of (AH3)4(R2O3)4 (molar mass = 478.17 g/mol)?
Please help. I've tried going (g of molecule/mol)x(1 mol of molecule/ 55.80g)but I'm not really sure what to do with this.
moles = grams/molar mass.
moles (AH3)4(R2O3)4 = 55.8/478.17 = ??
moles x 6.022 x 10^23 molecules/mole = # molecules present.
# R atoms is 8 x # molecules present.