A 0.25 mF capacitor is connected to a 9.0 V battery. What is the charge on the capacitor?
To find the charge on the capacitor, we can use the formula:
Q = C * V
where Q is the charge on the capacitor, C is the capacitance, and V is the voltage.
Given that the capacitance (C) is 0.25 mF (microfarads) and the voltage (V) is 9.0 V, we can substitute these values into the formula:
Q = 0.25 mF * 9.0 V
Now we need to convert the capacitance from microfarads to farads. There are 1,000,000 microfarads in a farad. So, 0.25 mF is equal to 0.25 × 10^-6 F.
Q = (0.25 × 10^-6 F) * 9.0 V
Multiplying the capacitance and voltage together, we get:
Q = 2.25 × 10^-6 C
Therefore, the charge on the capacitor is 2.25 microcoulombs (μC).
To find the charge on the capacitor, we need to use the formula:
Q = C * V
Where:
Q is the charge on the capacitor,
C is the capacitance of the capacitor, and
V is the voltage across the capacitor.
In this case, the capacitance (C) is given as 0.25 mF (millifarads), and the voltage (V) is 9.0 V.
Let's plug these values into the formula to find the charge:
Q = 0.25 mF * 9.0 V
Before we calculate, we need to convert the capacitance from millifarads (mF) to farads (F) since the SI unit for capacitance is farads. To convert millifarads to farads, we divide by 1000.
0.25 mF = 0.25 * (1/1000) F = 0.00025 F
Now, let's substitute the values into the formula:
Q = 0.00025 F * 9.0 V
Calculating further:
Q = 0.00225 C
Therefore, the charge on the capacitor is 0.00225 Coulombs.