a rectangle with perimeter of 198 cm is divided into 5 congruent rectangles. What is the perimeter of one of the five congruent rectangles?
i got the expression 5w + 4L = 198
the rectangle has two smaller rectangle on the top facing horizontally on the top and three smaller rectangles facing vertically in the bottom.
37
the answer would be 90. I know because my math teacher told me
To find the perimeter of one of the five congruent rectangles, we can use the given expression 5w + 4L = 198, where w represents the width of one congruent rectangle and L represents the length of one congruent rectangle.
Since the rectangle is divided into five congruent rectangles, we know that the length of the original rectangle is equal to three times the length of one congruent rectangle (3L) because there are three congruent rectangles vertically in the bottom.
Similarly, the width of the original rectangle is equal to two times the width of one congruent rectangle (2w) because there are two congruent rectangles horizontally on the top.
So, we can rewrite the given expression as 2w + 3L = 198.
To find the perimeter of one congruent rectangle, we need to divide the perimeter of the original rectangle by the number of congruent rectangles, which is 5.
So, we can set up the equation (2w + 3L) รท 5 = P, where P represents the perimeter of one congruent rectangle.
Now, we can solve for P:
2w + 3L = 5P
Let's rearrange the equation to solve for P:
5P = 2w + 3L
Dividing both sides of the equation by 5:
P = (2w + 3L) / 5
Therefore, the perimeter of one of the five congruent rectangles is (2w + 3L) divided by 5.
Please note that without the specific values for w and L, we cannot determine the exact numerical value of the perimeter of one congruent rectangle.