A student's scores on four math tests were 89,92,95, and 85. What will he need to make on the 5th test to have an average of 93? is this possible?
HELP!
An average of 93 requires a total of 93x5 = 465
The total after four tests was 361
Is a test score of 104 possible?
Not if it is the % correct
is this right
To find out what score the student needs to make on the 5th test in order to have an average of 93, we can use the following steps:
Step 1: Add up the scores of the four tests: 89 + 92 + 95 + 85 = 361.
Step 2: Divide the sum by 4 to find the current average: 361 / 4 = 90.25.
Step 3: Subtract the current average from the desired average: 93 - 90.25 = 2.75.
Step 4: To achieve an average of 93, the student needs a total of 93 * 5 = 465 points in total.
Step 5: Subtract the sum of the current scores from the desired total: 465 - 361 = 104.
Therefore, the student would need to score at least 104 on the 5th test in order to achieve an overall average of 93. However, since the maximum possible score on a test is 100, it is not possible for the student to achieve an average of 93 with the given test scores.
To find out what score the student needs on the 5th test to have an average of 93, we need to use the formula for calculating the average.
Average = Sum of scores / Number of scores
In this case, the student has taken 4 tests, and the desired average is 93. Thus, the sum of the scores on the four tests should be 93 multiplied by 4 (the total number of tests) to get the sum of all five tests.
Sum of scores = Average × Number of scores
Sum of scores = 93 × 5 = 465
Now, to determine what score the student needs on the 5th test, we can subtract the cumulative score on the four tests (89 + 92 + 95 + 85) from the desired sum of scores (465).
Score needed on 5th test = Sum of scores - Cumulative score on four tests
Score needed on 5th test = 465 - (89 + 92 + 95 + 85)
Score needed on 5th test = 465 - 361
Score needed on 5th test = 104
Therefore, the student needs to score at least 104 on the 5th test to achieve an average of 93. Whether this is possible or not depends on the grading scale and the difficulty of the 5th test.