d=(1/2)at^2; solve for a.
i got a=d/([1/5])t^2) but i don't see that in any of the possible responses:
a. a= (2d)/t^2
b. a= 2dt^2
c. a= (dt^2)/2
d. a= d/2t^2
What did I do wrong?
& can you please show detailed work?
To solve for "a" in the equation d = (1/2)at^2, we can follow the steps below:
Given: d = (1/2)at^2
Step 1: Multiply both sides of the equation by 2 to eliminate the fraction.
2d = at^2
Step 2: Divide both sides of the equation by t^2 to isolate "a".
(2d) / t^2 = a
Based on the steps above, the correct answer is a = (2d) / t^2.
However, you made a mistake in your calculation. Let's go through your steps:
Given: d = (1/2)at^2
Step 1: You correctly multiplied both sides by 2 to eliminate the fraction:
2d = at^2
Step 2: Instead of dividing both sides by t^2, you divided by 1/5t^2, which is incorrect. The correct division is by t^2:
2d / t^2 = a
OR
a = 2d / t^2
Therefore, the correct answer is a = (2d) / t^2, which matches option (a).