finf y'' by implict differentiation
√x + √y = 1
√x+√y = 1
differentiate with respect to x:
1/(2√x) + (1/2√y) dy/dx =0
Substitute √y by 1-√x:
1/(2√x) + (1/2(1-√x)) dy/dx =0
Solve for dy/dx.
√x + √y = 1
differentiate with respect to x:
1/(2√x) + (1/2√y) dy/dx =0
Substitute √y by 1-√x:
1/(2√x) + (1/2(1-√x)) dy/dx =0
Solve for dy/dx.