# CHEM- solution/freezing piont

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a solution of sulfur (2.560g) in naphthalene (100g) freezes 0.68K lower the freezing point of pure naphthalene (353.10K). for naphthalene, Kf= 6.8K kg mol. calculatem the molecular formula of the sulfur dissolved in the naphthalene?

• CHEM- solution/freezing piont -

delta = Kf*molality
Solve for molality

molality = moles/kg solvent.
Solve for moles

moles = grams/molar mass
solve for molar mass.

• CHEM- solution/freezing piont -

so, 0.68K/6.8 K kg mol= 0.1kg/mol (m)
then 0.1/32g/mol= 3.1*10^-3
then (3.1*10^-3)*(2.56g)= 8*10^-3
does that make it S8, i don't get that part.

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