Copper metal can be obtained by heating copper oxide in the presence of carbon monoxide, CO, according to the reaction:
CuO(s) + CO(g) --> Cu(s) + CO2(g)
Calculate Delta H° in kJ using the following thermochemical equations.
Reactions
2CO(g) + O2(g) --> 2CO2(g) DeltaH° -566.1
2Cu(s) + O2(g) --> 2CuO(s) DeltaH° -310.5
Take 1/2 equation 2.
Take 1/2 equation 2 and reverse it (and delta H).
Add the two.
Delta H equals to -876.6
To calculate ΔH° for the reaction CuO(s) + CO(g) → Cu(s) + CO2(g), we can use the given thermochemical equations to calculate the overall enthalpy change.
1. First, notice that the equation we want to find ΔH° for can be obtained by combining the two given thermochemical equations in a way that cancels out the common species, O2:
2Cu(s) + O2(g) → 2CuO(s) (multiplied by 2)
2CuO(s) + 2CO(g) → 2Cu(s) + 2CO2(g)
2. Now, we can add the two equations together to obtain the desired equation:
2CuO(s) + 2CO(g) + 2Cu(s) + 2CO2(g)
3. Adding the enthalpy changes of the individual reactions, we get:
ΔH° = (-310.5 kJ/mol) + (-566.1 kJ/mol)
4. Calculate the sum:
ΔH° = -876.6 kJ/mol
Therefore, the ΔH° for the reaction CuO(s) + CO(g) → Cu(s) + CO2(g) is -876.6 kJ/mol.