A 1260.4 kg car is traveling at 21.5 m/s when
the driver takes his foot off the gas pedal. It
takes 4 s for the car to slow down to 20 m/s.
How large is the net force slowing the car?
Answer in units of N.
252.08 kg/s/s
how did u get that answer
To find the net force slowing the car, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration. In this case, the car is slowing down, so its acceleration is negative.
First, let's calculate the change in velocity of the car:
Δv = final velocity - initial velocity = 20 m/s - 21.5 m/s = -1.5 m/s
Next, let's calculate the acceleration of the car:
acceleration = Δv / Δt = -1.5 m/s / 4 s = -0.375 m/s^2
Now we can find the net force:
F_net = mass * acceleration = 1260.4 kg * (-0.375 m/s^2)
F_net ≈ -472.65 N
Since force is a vector quantity, the negative sign indicates that the force is acting in the opposite direction of the car's motion, which is necessary to slow it down. Therefore, the net force slowing the car is approximately 472.65 N in the opposite direction of its motion.