A volume of 0.285 L of a gas at STP weighs 0.537 g. Calculate the molar mass of the gas.
A mole of gas occupies 22.4 L at STP. So what's the mass of 22.4L of this gas?
so
(1)(.285)=(22.4)(273.15)
what do I do next?
To calculate the molar mass of the gas, we need to use the ideal gas law equation: PV = nRT.
At STP (Standard Temperature and Pressure), the values are:
- Temperature (T) = 273.15 K
- Pressure (P) = 1 atm
First, let's rearrange the equation to solve for the number of moles (n):
n = PV / RT
Now, plug in the given values:
Volume (V) = 0.285 L
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 L.atm/mol.K
Temperature (T) = 273.15 K
n = (1 atm * 0.285 L) / (0.0821 L.atm/mol.K * 273.15 K)
Calculate:
n = 0.0106 mol (approximately)
Next, we need to calculate the mass of the gas using the given weight:
mass = 0.537 g
Now, we can determine the molar mass using the formula:
Molar mass (M) = mass / n
M = 0.537 g / 0.0106 mol
Calculate:
M = 50.66 g/mol
Therefore, the molar mass of the gas is approximately 50.66 g/mol.