During an Olympic bobsled run, the Jamaican team makes a turn of radius 7.6 m at a speed of 96.6 km/h. What is their acceleration in terms of g?

Compare V^2/R (their acceleration) to g.

Before using the formula, convert the 96.6 km/h speed to m/s by multiplying by the appropriate factors, 1000 m/km and 1/3600 h/s.

To find the acceleration in terms of g, we first need to convert the speed from km/h to m/s.

1 km/h = 1000 m / 3600 s

So, the speed in m/s is:

96.6 km/h * (1000 m / 3600 s) = 26.83 m/s

Next, we can calculate the centripetal acceleration using the formula:

ac = (v^2) / r

where ac is the centripetal acceleration, v is the speed, and r is the radius.

ac = (26.83 m/s)^2 / 7.6 m
= 961.3489 m^2/s^2 / 7.6 m
= 126.6242 m/s^2

Finally, we can convert the centripetal acceleration to g by dividing it by the acceleration due to gravity.

g ≈ 9.8 m/s^2

ac_g = 126.6242 m/s^2 / 9.8 m/s^2
≈ 12.92 g

Therefore, the acceleration of the Jamaican team during the bobsled run is approximately 12.92 g.

To find the acceleration of the Jamaican bobsled team in terms of "g" (acceleration due to gravity), we can use the centripetal acceleration formula:

a = v² / r

where:
a is the centripetal acceleration,
v is the velocity, and
r is the radius of the turn.

First, let's convert the velocity from km/h to m/s. We know that 1 km/h is equal to 0.2778 m/s.

v = 96.6 km/h * (0.2778 m/s / 1 km/h) = 26.833 m/s

Now, we can substitute the values in the formula:

a = (26.833 m/s)² / 7.6 m
a = 719.916289 / 7.6
a ≈ 94.73 m/s²

To express the acceleration in terms of "g," we divide it by the acceleration due to gravity, which is approximately 9.8 m/s².

a/g = 94.73 m/s² / 9.8 m/s²
a/g ≈ 9.68

Therefore, the acceleration of the Jamaican bobsled team is approximately 9.68g.