Please checkReiny
posted by Michelle
Could you check these two problems?
3sqrt (y+2) = 3 is y = 25
Answers were: true or false
I said true because I did it like this
Square both sides=y + 2 = 3^3
y+2 = 27
y = 25
and sqrt (2y6) = 3y for y
answes are:
no solution
5
3,5
3
I said 3 because I did it like this:
8y 15 + y^2 = 0
y^2 + 8y 15 =0
(y5) (y+3) = 0
Y = 3,5 but five doesn't work only 3
Can you please checkI didn't put all the steps for the second oneit was too long

Reiny
you forgot about the 3 in front of 3√(y+2) when you squared
should be
9(y+2) = 9
y+2 = 1
y = 1
check:
LS = 3√(1+2) = 3√1 = 3
RS = 3
so y = 1
for the second watch your simplifation, my final quadratic was
y^2  8y + 15 = 0
(y3)(y5) = 0
y = 3 or y = 5
You should have had y = 3
you are right in the conclusion, only x = 3 verifies. 
Michelle
Thanks I think I somewhat get itThanks again for the explanations
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