A titration. 12.46 mL of KMnO4 are titrated with 25 mL of H2C2O4. The half reaction is 2H2O+H2C2O4 ARROW 2H2CO3+2H+2e-. How do I get the molarity of H2C2O4? PLEASE HELP
You must add the half reaction of KMnO4 to that of H2C2O4, with each half reaction multiplied by a number so that the electrons gained = electrons lost.
Then moles KMnO4 = M x L
Using the coefficients in the balanced equation, convert moles KMnO4 to moles H2C2O4. Finally, M H2C2O4 = moles H2C2O4/L H2C2O4.