A solution contains an unknown amount of dissolved magnesium (Mg 2+). Addition of 5.50×10^−2 mol of Na2CO3 causes complete precipitation of all of the magnesium. what mass of the magnesium was dissolved in the solution? answer in unit g.
First write and balance the equation.
Mg^+2 + Na2CO3 ==> 2Na^+ + MgCO3.
You know how many moles Na2CO3 were used. Convert mole Na2CO3 to moles Mg using the coefficients in the balanced equation. Then convert moles Mg to grams. g = moles x molar mass.
To find the mass of the magnesium dissolved in the solution, we can use stoichiometry and the molar masses of the compounds involved.
First, we need to find the number of moles of Mg2+ in the given amount of Na2CO3. The chemical equation involved is:
Mg2+ + CO32- → MgCO3
From the equation, we can see that the stoichiometric ratio is 1:1. This means that for every 1 mole of Mg2+, we need 1 mole of Na2CO3. Therefore, the number of moles of Mg2+ is equal to the number of moles of Na2CO3 added.
Given: 5.50×10^-2 mol of Na2CO3
So, the number of moles of Mg2+ = 5.50×10^-2 mol
Next, we need to determine the molar mass of MgCO3, which is the precipitate formed.
MgCO3 = (1 × atomic mass of Mg) + (1 × atomic mass of C) + (3 × atomic mass of O)
MgCO3 = (1 × 24.31 g/mol) + (1 × 12.01 g/mol) + (3 × 16.00 g/mol)
MgCO3 = 24.31 g/mol + 12.01 g/mol + 48.00 g/mol
MgCO3 = 84.32 g/mol
Now, using the stoichiometry and molar mass of MgCO3, we can calculate the mass of Mg2+:
Mass of Mg2+ = (number of moles of Mg2+) × (molar mass of MgCO3)
Mass of Mg2+ = (5.50×10^-2 mol) × (84.32 g/mol)
Mass of Mg2+ ≈ 4.67 g
Therefore, the mass of the magnesium dissolved in the solution is approximately 4.67 grams.
To find the mass of magnesium dissolved in the solution, we'll use the given information and the balanced chemical equation for the reaction between magnesium ions (Mg2+) and carbonate ions (CO32-) to form magnesium carbonate (MgCO3).
The balanced chemical equation for the reaction is:
Mg2+ + CO32- → MgCO3
From the equation, we can see that 1 mole of magnesium ions (Mg2+) reacts with 1 mole of carbonate ions (CO32-) to produce 1 mole of magnesium carbonate (MgCO3).
Given: 5.50×10^−2 mol of Na2CO3 (carbonate ions)
Since every mole of carbonate ions reacts with 1 mole of magnesium ions, the number of moles of magnesium ions (Mg2+) is also 5.50×10^−2 mol.
To calculate the mass of magnesium, we need to know the molar mass of magnesium (Mg), which is 24.31 g/mol.
Now, we can calculate the mass of magnesium dissolved in the solution:
Mass (g) = Number of moles × Molar mass
Mass (g) = 5.50×10^−2 mol × 24.31 g/mol
Mass (g) ≈ 1.34 g
Therefore, the mass of magnesium dissolved in the solution is approximately 1.34 grams.