A diagram represents a simplified sketch of an electric DC motor.which contains a magnet, commutator, carbon brushes, coil and a pivot. when the electric motor is connected to a 12V DC supply, it draws a current of 1,2A. The motor is now used to lift an object of mass 1,6kg through a vertical height of 0,08m at constant speed in 3s. IS ALL THE ELECTRICAL ENERGY CONVERTED TO THE GAIN IN POTENTIAL ENERGY OF THE OBJECT? SUPPORT YOUR ANSWER WITH RELEVANT CALCULATIONS.
When did it draw 1.2 a? under no load, or under load?
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To determine if all the electrical energy is converted to the gain in potential energy of the object, we need to calculate the electrical energy input and compare it to the change in potential energy of the object.
First, let's calculate the electrical energy input to the motor using the formula:
Electrical Energy (E) = Voltage (V) * Current (I) * Time (t)
Given:
- Voltage (V) = 12V
- Current (I) = 1.2A
- Time (t) = 3s
Substituting the values into the formula, we get:
E = 12V * 1.2A * 3s
E = 43.2 Joules
Now, let's calculate the change in potential energy of the object using the formula:
Change in Potential Energy (ΔPE) = Mass (m) * Gravity (g) * Height (h)
Given:
- Mass (m) = 1.6kg
- Gravity (g) = 9.8 m/s^2
- Height (h) = 0.08m
Substituting the values into the formula, we get:
ΔPE = 1.6kg * 9.8 m/s^2 * 0.08m
ΔPE = 1.2544 Joules
Comparing the electrical energy input (43.2 Joules) to the change in potential energy (1.2544 Joules), we can see that the electrical energy input is much higher than the change in potential energy.
Therefore, not all the electrical energy is converted to the gain in potential energy of the object. Some of the electrical energy is lost as heat, sound, and other forms of energy due to inefficiencies in the motor and mechanical system.