What number am I

My tens digit is double my ones digit. I am less than 70 greater than 60?

How do u figure this out need help to explain how to get the answer..

x + 20 x = 21 x

60 < 21 x <70

try x = 3

63

Alternatively

"If I am less than 70 greater than 60? "

then the possibles are 61, 61 ....69

so the tens is always 6

then if
"My tens digit is double my ones digit."

then the ones digit is 6/2=3

thus the answer is 63.

If the number is less than 70 and greater than 60, the tens digit has to be 6. Now, if the ones digit is half the tens digit, divide 6 in half. The answer is 63.

same as the others 63

53-35

To find the number that meets the given conditions, we can set up a system of equations and solve for the variables.

Let's call the ones digit "x" and the tens digit "2x" (since the tens digit is double the ones digit).

According to the given conditions:
1. The number is less than 70, which means the tens digit is less than 7.
2. The number is greater than 60, which means the tens digit is greater than 6.

Now we can form the two equations:
Equation 1: 2x < 7
Equation 2: 10 + 2x > 60

Solving Equation 1:
Since we want the tens digit to be less than 7, we can try different values for x and find the largest value that satisfies the inequality.
If we try x = 3, 2x = 6, which is less than 7. So, this value satisfies the condition.

Solving Equation 2:
We want the tens digit to be greater than 6, so we need to find the smallest value for x that satisfies the inequality.
If we try x = 3, 2x = 6. Now, if we substitute these values into the inequality: 10 + 6 = 16, which is greater than 60. So, this value does not satisfy the condition.

Therefore, the correct value for x is 3. The ones digit is 3, and the tens digit is double that, which is 6. Thus, the number you are is 63.