a bunsen burner flame takes 8 minutes to raise 250g of water from 20 degrees to 100 degrees celcius, when the water is in a beaker of mass 100g (c=0.67J/g degrees celcuius). How long will i take to raise the temperature of 200g of glycerin (c=2.43J/g degrees celcius) contained in the same beaker from 20 to 80 degrees celcius?
i don't get this, could you explain in details or could u tell me the ans. so i could verify my answer. thanks
The heat required to raise the beaker temperature will be 3/4 as much the second time, becasue of the delta-T rTIO. The heat required to heat the liquid will be higher by a factor (200/250)(2.43/0.67) = 2.90
Calculate the total heat required in the second case. The ratio (heat)2/(heat1) wilL be the ratio of the heating times required, assuming the heaT transfer rate of the burner is the same.
To find the time it takes to raise the temperature of glycerin, we can use the equation:
Q = mcΔT
where Q is the heat energy absorbed or released, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
First, let's calculate the heat energy absorbed by water in the beaker:
Q_water = (m_water + m_beaker) * c_water * ΔT_water
Given:
m_water = 250g
m_beaker = 100g
c_water = 0.67J/g°C
ΔT_water = 100°C - 20°C = 80°C
Q_water = (250g + 100g) * 0.67J/g°C * 80°C
Q_water = 350g * 0.67J/g°C * 80°C
Q_water = 18760J
Next, let's calculate the heat energy required to raise the temperature of glycerin:
Q_glycerin = (m_glycerin + m_beaker) * c_glycerin * ΔT_glycerin
Given:
m_glycerin = 200g
m_beaker = 100g
c_glycerin = 2.43J/g°C
ΔT_glycerin = 80°C - 20°C = 60°C
Q_glycerin = (200g + 100g) * 2.43J/g°C * 60°C
Q_glycerin = 300g * 2.43J/g°C * 60°C
Q_glycerin = 43740J
Now, we can find the time required to raise the temperature of glycerin using the heat energy equation:
Q = mcΔT
Since Q = mcΔT and Q is the same for both water and glycerin (Q_water = Q_glycerin), we can set them equal to each other:
(250g + 100g) * 0.67J/g°C * 80°C = (200g + 100g) * 2.43J/g°C * 60°C
Simplifying the equation:
350g * 0.67J/g°C * 80°C = 300g * 2.43J/g°C * 60°C
Rearranging and solving for time:
Time_glycerin = (350g * 0.67J/g°C * 80°C) / (300g * 2.43J/g°C * 60°C)
Time_glycerin = 112560J / 43740J
Time_glycerin ≈ 2.57 minutes
Therefore, it will take approximately 2.57 minutes to raise the temperature of 200g of glycerin from 20 to 80 degrees Celsius in the same beaker.
To find out how long it will take to raise the temperature of glycerin, we can use the equation:
q = mcΔT
where:
q = heat energy gained or lost by the substance (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g degrees Celsius)
ΔT = change in temperature (in degrees Celsius)
First, let's find the heat energy gained by the water using the given information:
m = 250g (mass of water)
c = 0.67 J/g degrees Celsius (specific heat capacity of water)
ΔT = 100 - 20 = 80 degrees Celsius (change in temperature)
q_water = mcΔT
q_water = 250g * 0.67 J/g degrees Celsius * 80 degrees Celsius
q_water = 13400 J
Next, we need to find the time it takes to raise the temperature of the water:
time_water = 8 minutes
Now, let's find the heat energy required to raise the temperature of glycerin:
m = 200g (mass of glycerin)
c = 2.43 J/g degrees Celsius (specific heat capacity of glycerin)
ΔT = 80 - 20 = 60 degrees Celsius (change in temperature)
q_glycerin = mcΔT
q_glycerin = 200g * 2.43 J/g degrees Celsius * 60 degrees Celsius
q_glycerin = 29160 J
Finally, let's find the time it will take to raise the temperature of the glycerin:
time_glycerin = q_glycerin / q_water * time_water
time_glycerin = 29160 J / 13400 J * 8 minutes
Now we can calculate the answer:
time_glycerin = 17.33 minutes (rounded to two decimal places)
Therefore, it will take approximately 17.33 minutes to raise the temperature of 200g of glycerin in the same beaker from 20 to 80 degrees Celsius using a Bunsen burner flame.