Na3PO4(aq) + AlCl3(aq) produces? Complete and balance each of the following equations. If no reaction occurs, write NOREACTION.
3NaCl(aq)+AlPO@SUB{4}(s)
==> AlPO4 + NaCl
You balance.
To balance the equation and determine the products, we need to consult the solubility rules and the reactivity series.
First, let's balance the equation:
Na3PO4(aq) + AlCl3(aq) →
To balance the sodium (Na) and aluminum (Al) atoms, we need three sodium atoms and one aluminum atom:
3Na3PO4(aq) + AlCl3(aq) →
Next, let's determine the products by considering the solubility rules and the reactivity series:
Na3PO4 is a soluble salt, so it will dissociate into its ions:
3Na3PO4(aq) → 9Na+(aq) + 3PO4^3-(aq)
AlCl3 is also a soluble salt, so it will dissociate into its ions:
AlCl3(aq) → Al3+(aq) + 3Cl-(aq)
Now, let's examine the possible reactions between the ions.
Aluminum (Al3+) is more reactive than sodium (Na+), so it can displace sodium from the sodium phosphate compound. This will result in the formation of aluminum phosphate (AlPO4) and sodium chloride (NaCl).
Therefore, the balanced equation is:
3Na3PO4(aq) + AlCl3(aq) → AlPO4(s) + 9NaCl(aq)
The products are aluminum phosphate (AlPO4, solid) and sodium chloride (NaCl, aqueous).
To determine the products of the chemical reaction between Na3PO4(aq) and AlCl3(aq), we need to use the principles of double replacement or precipitation reactions. In such reactions, the positive ions (cations) in the reactants swap with each other, resulting in the formation of new compounds.
Step 1: Write down the balanced molecular equation:
Na3PO4(aq) + AlCl3(aq) → ?
Step 2: Identify and write the formulas of the cations and anions involved:
The cations are Na+ (from Na3PO4) and Al3+ (from AlCl3).
The anions are PO43- (from Na3PO4) and Cl- (from AlCl3).
Step 3: Swap the cations:
Na+ swaps with Al3+, resulting in NaAl (sodium aluminum).
Step 4: Write the balanced equation:
Na3PO4(aq) + AlCl3(aq) → NaAl + Cl- + PO43-
However, this equation is not yet balanced. To balance it, we need to make sure that the number of atoms of each element is the same on both sides of the equation.
Step 5: Balance the equation:
Since there is one chloride ion on the left side, we need three chloride ions on the right side to balance the equation. We can achieve this by multiplying AlCl3 by 3:
Na3PO4(aq) + 3 AlCl3(aq) → NaAl + 3 Cl- + PO43-
Now the equation is balanced.
Therefore, the balanced equation for the reaction between Na3PO4(aq) and AlCl3(aq) is:
Na3PO4(aq) + 3 AlCl3(aq) → NaAl + 3 Cl- + PO43-