# chemistry

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What volume of 0.174M Na3PO4 solution is necessary to completely react with 89.1mL of 0.106M CuCl2?

2Na3PO4(aq) + 3CuCl2(aq) produces Cu3(PO4)2(s)+ 6NaCl(aq)

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1. ### chemistry

2Na3PO4 + 3CaCl2 ----> Ca3 (PO4)2 + 6NaCl how many moles of CaCl2 remain if .10 mol Na3PO4 and .40 mol CaCl2 are used?
2. ### Chemistry URGENT

Could someone write out the total ionic equation and the net ionic equation for: 2Na3PO4 (aq) + 3CuSO4 • 5H2O (aq) → Cu3 (PO4)2 (s) + 3Na3SO4 (aq) + 15H2O (l) Cu ++ + PO 4 --- >>> Cu3 (PO4)2 (s) Of course, it needs …
3. ### Chemistry

What volume of 0.174 M Na3PO4 solution is necessary to completely react with 89.1 mL of 0.106 M CuCl2?
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3Ca(NO3)2(aq)+2Na3PO4(aq)->Ca3(PO4)2(s)+6NaNO3(aq) (a) the grams of Ca3(PO4)2 that can be obtained from 126 mL of 0.750 M Ca(NO3)2 (b) the volume of 0.10 M Na3PO4 needed to react with 13 mL of 0.30 M Ca3(NO3)2 (c) the molarity (M) …
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Refer to 3CuCl2 (aq)+2Na3PO4 (aq) = Cu3(PO4)2+6NaCl (aq) If a student started with 18 grams of CuCl2 and enough Na3PO4 to completely react, how many grams of Cu3(PO4)2 will (theoretically) be produced?
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3CaCl2+2Na3PO4 -----------> 1Ca3(PO4)2+6NaCl Did I correctly balance this equation?
8. ### chemistry

Consider the following reaction: 2Na3PO4(aq)+3CuCl2(aq) = Cu3(PO4)2(s)+ 6NaCl(aq) If 75mL of .175 M Na3PO4 combined with 95mL of .102M CuCl2, determine the concentration of the excess reagent.
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What volume of 0.159 M Na3PO4 solution is necessary to completely react with 92.6 mL of 0.119 M CuCl2?
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What volume of 0.182 M Na3PO4 solution is necessary to completely react with 95.1 mL of 0.117 M CuCl2?

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