4C3H5N3O9 -> 6N2 + 12 CO2 + 10H20 + O2

a) how many grams of water would be produced if 75 g of nitroglycerin decompose?
b) The creation of 3.89 moles of CO2 would require how many grams of nitroglycerin?

how many moles of nitro is 75g. You get 10/4 *molesNitro of water. Convert that to grams.

To answer these questions, we need to use the balanced chemical equation given:

4C3H5N3O9 -> 6N2 + 12 CO2 + 10H2O + O2

a) To determine the number of grams of water produced, we can look at the balanced equation. The coefficient of water (H2O) is 10. This means that for every 10 moles of nitroglycerin that decompose, 10 moles of water will be produced.

Now, let's calculate the molar mass of water (H2O):
2(1.008 g/mol) + 16.00 g/mol = 18.016 g/mol

Next, we need to convert the given mass of nitroglycerin (75 g) into moles. To do this, we'll use the molar mass of nitroglycerin:
4(12.011 g/mol) + 3(1.008 g/mol) + 5(14.007 g/mol) + 9(16.00 g/mol) = 227.08 g/mol

75 g / 227.08 g/mol = 0.33 moles of nitroglycerin

Since the ratio of nitroglycerin to water is 1:10, we can calculate the moles of water produced:
0.33 moles * 10 = 3.3 moles of water

Finally, we can convert the moles of water into grams:
3.3 moles * 18.016 g/mol = 59.5 g of water

Therefore, if 75 g of nitroglycerin decompose, approximately 59.5 grams of water would be produced.

b) To determine how many grams of nitroglycerin are needed to produce 3.89 moles of CO2, we will use the same balanced equation.

The ratio of nitroglycerin to CO2 is 4:12. From the equation, we can see that for every 4 moles of nitroglycerin, 12 moles of CO2 are produced.

First, let's calculate the molar mass of CO2:
12.011 g/mol + 2(16.00 g/mol) = 44.01 g/mol

Next, using the mole ratio, we can find the moles of nitroglycerin:
3.89 moles of CO2 * (4 moles of nitroglycerin / 12 moles of CO2) = 1.30 moles of nitroglycerin

Finally, we convert the moles of nitroglycerin into grams using the molar mass of nitroglycerin:
1.30 moles * 227.08 g/mol = 295.4 g of nitroglycerin

Therefore, the creation of 3.89 moles of CO2 would require approximately 295.4 grams of nitroglycerin.