An electron with a speed of 1.3 × 107 m/s moves horizontally into a region where a constant vertical force of 4.4 × 10-16 N acts on it. The mass of the electron is 9.11 × 10-31 kg. Determine the vertical distance the electron is deflected during the time it has moved 29 mm horizontally.
i am putting 2.4 mm but its a wrong answer
2.4mm
To determine the vertical distance the electron is deflected, we need to use the given information about the speed, force, and mass of the electron.
First, let's analyze the horizontal motion of the electron. We are given that the electron has moved 29 mm horizontally. We can convert this distance to meters by dividing it by 1000:
29 mm / 1000 = 0.029 m
Next, let's calculate the time it takes for the electron to cover this distance. We can use the formula: distance = speed * time.
Since the speed of the electron is given as 1.3 × 107 m/s, we can rearrange the formula to solve for time:
time = distance / speed = 0.029 m / (1.3 × 107 m/s)
Now, we can calculate the vertical distance the electron is deflected during this time. We can use the formula: force = mass * acceleration.
Since we are given the force as 4.4 × 10-16 N and the mass of the electron as 9.11 × 10-31 kg, we can rearrange the formula to solve for acceleration:
acceleration = force / mass = (4.4 × 10-16 N) / (9.11 × 10-31 kg)
Finally, we can use the formula for vertical displacement to determine the vertical distance the electron is deflected during the calculated time:
vertical distance = 0.5 * acceleration * time^2
Now, we can plug in the values and calculate the vertical distance:
vertical distance = 0.5 * (4.4 × 10-16 N) / (9.11 × 10-31 kg) * (0.029 m / (1.3 × 107 m/s))^2
Evaluating this expression will give you the correct answer for the vertical distance the electron is deflected during the time it has moved 29 mm horizontally.