posted by julia .
A man pulls a crate of mass 61.0 kg across a level floor. He pulls with a force of 178.0 N at an angle of 20.0� above the horizontal. When the crate is moving, the frictional force between the floor and the crate has a magnitude of 124.0 N.
If the crate starts from rest, how fast will it be moving after the man has pulled it a distance of 2.90 m?
Calculate the acceleration a using
F = M a a = F/M
F = 178.0 cos 20 - 124.0 N
The velocity after moving a distance X is sqrt(2aX)