A ball of mass 0.540 kg moving east (+x direction) with a speed of 3.30 m/s collides head-on with a 0.740 kg ball at rest. If the collision is perfectly elastic, what will be the speed and direction of each ball after the collision?

a)ball originally at rest m/s
b)ball originally moving east m/s

http://www.jiskha.com/display.cgi?id=1259111298

i got -.5156 and 2.785 but both are wrong

The procedure laid out is exact. Recheck your math.

To find the speed and direction of each ball after the collision, we can use the principle of conservation of momentum and kinetic energy.

1. Conservation of momentum:
Since the collision is perfectly elastic, the total momentum before the collision should be equal to the total momentum after the collision.

Momentum before collision = Momentum after collision

Momentum (p) = mass (m) x velocity (v)

Let's assume the initial velocity of the ball at rest (ball 2) is u2, and the final velocities of ball 1 and ball 2 are v1 and v2, respectively.

The momentum before collision can be expressed as:
p_initial = m1 * u1 + m2 * u2
(Since ball 2 is at rest, u2 = 0)
= m1 * u1

The momentum after collision can be expressed as:
p_final = m1 * v1 + m2 * v2

Since the collision is perfectly elastic, we know that the total kinetic energy of the system is conserved.

2. Conservation of kinetic energy:
The kinetic energy before collision should be the same as the kinetic energy after collision.

Kinetic energy (KE) = (1/2) * mass * velocity^2

Let's express the total kinetic energy before collision as:
KE_initial = (1/2) * m1 * u1^2

And the total kinetic energy after the collision as:
KE_final = (1/2) * m1 * v1^2 + (1/2) * m2 * v2^2

Now, we can equate the momentum and kinetic energy equations to find the values of v1 and v2.

1. Momentum equation:
m1 * u1 = m1 * v1 + m2 * v2 (Equation 1)

2. Kinetic energy equation:
(1/2) * m1 * u1^2 = (1/2) * m1 * v1^2 + (1/2) * m2 * v2^2 (Equation 2)

From Equation 1, we can isolate v2:
v2 = (m1 * u1 - m1 * v1) / m2

Substituting this value of v2 into Equation 2, we can solve for v1:
(1/2) * m1 * u1^2 = (1/2) * m1 * v1^2 + (1/2) * m2 * ((m1 * u1 - m1 * v1) / m2)^2

Simplifying this equation will give us the value of v1.

Once we have v1, we can substitute it back into Equation 1 to find v2.

By solving these equations, we can determine the final velocities (speed and direction) of each ball after the collision.