physics
posted by Andrew .
An elevator and its load have a combined mass of 1700 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 13 m/s, is brought to rest with constant acceleration in a distance of 43 m.

The cable tension will increase to
T = M(g+a)
when the elevator is slowing down at deceleration rate a.
You can get a from the relation
V^2/2 = a X
where X is the stopping distance, and V is the initial velocity. 
6089

169/2=a*43
84.5=a*43
a=84.5/43
a=1.965
T=M(g+a)
T=1700(9.8+1.965)
T=1700*(7.835)
T=13,319.5
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