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An elevator and its load have a combined mass of 1700 kg. Find the tension in the supporting cable when the elevator, originally moving downward at 13 m/s, is brought to rest with constant acceleration in a distance of 43 m.

  • physics -

    The cable tension will increase to
    T = M(g+a)
    when the elevator is slowing down at deceleration rate a.

    You can get a from the relation
    V^2/2 = a X
    where X is the stopping distance, and V is the initial velocity.

  • physics -

    6089

  • physics -

    169/2=a*43
    84.5=a*43
    a=84.5/43
    a=1.965
    T=M(g+a)
    T=1700(-9.8+1.965)
    T=1700*(-7.835)
    T=-13,319.5

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