Volume (cm3 Area(cm2) Thickness (cm)
.20 cm3 100 cm2 0.002 cm
.28 cm3 122 cm2 0.002 cm
.24 cm3 144 cm2 0.017 cm
.41 cm3 225 cm2 0.0018cm
If you had used a very crude balance that allowed only one significant figure, how would this have affected your results for: Area? Volume? Thickness?
Could this method be used to determine the thickness of an oil spill? What information would be needed?
slope --y = 49.4x - 30
What does the slope tell about the thickness
By mistake, a quart of oil (1.06 quarts = 1 liter = 1000 cm3) was dumped into a
swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm3. How thick was the resulting oil slick? Be careful with significant figures and exponential notation. Density is not needed to calculate the answer for this problem.
How might this method of finding thickness be used in finding the size of molecules?
1. Basically, it would influence your results, making them either too high, or too low. The effect of your crude balance would be compounded. Your results likely would be too high, compared to the true value.
2. Yes, assuming the spill is uniformly spread on top of the water surface, and the surface is perfectly still. As long as these conditions persist, the thickness of the spill can be calculated if one knows the mass of the total value of the oil spilt, the density of the oil, and the surface area that the oil covers.
3. You would have to tell us what you're graphing for an adequate answer to be given.
4. d_oil = m_oil/v_oil
m_oil = d_oil * v_oil
T_oil = m_oil/(d_oil * A_oil)
T_oil = (d_oil * v_oil)/(d_oil * A_oil)
T_oil = = v_oil / A_oil
T_oil = (1000cm^3)/(2 500cm * 3 000cm)
T_oil = 1.33 x 10^-4cm
5. This method might be used in finding the size of molecules, by layering it on a flat surface with a known mass, such that it is very thin (approximately 1 molecule thin). Then, knowing the difference in mass, and the area, the size of molecules can be easily determined.
Well, if you had used a very crude balance that allowed only one significant figure, it would have affected your results for area, volume, and thickness. The area would be rounded to 100 cm2 for all measurements, the volume would be rounded to 0.2 cm3, 0.3 cm3, 0.2 cm3, and 0.4 cm3, and the thickness would be rounded to 0.002 cm for all measurements.
Using this method to determine the thickness of an oil spill wouldn't be very accurate. In order to determine the thickness, you would need more information like the area of the spill and the overall volume. Additionally, a more precise balance would be needed to get an accurate measurement.
As for the equation slope --y = 49.4x - 30, the slope tells us about the relationship between the variables. In this case, it tells us that for every increase of 1 in x, there is an increase of 49.4 in y. So, the slope indicates the rate of change in thickness.
Now, with the quart of oil spilled in the swimming pool, let's calculate the thickness of the resulting oil slick. First, we need to convert the area of the pool to cm2, which is 7500 cm2 (25.0 m x 30.0 m). Then, we can divide the volume of the oil (1000 cm3) by the area to get the thickness:
Thickness = Volume / Area
Thickness = 1000 cm3 / 7500 cm2
Thickness = 0.133 cm
So, the resulting oil slick would have a thickness of approximately 0.133 cm.
In terms of finding the size of molecules, a similar method can be used. By measuring the volume and area of a sample with a known number of molecules, we can calculate the average size of each molecule. It's a simplified way to estimate their size. However, more precise methods and equipment would be required for accurate measurements.
If a very crude balance that allowed only one significant figure was used, the following calculations would be affected in the following ways:
- Area: The area would be rounded to the nearest tenth or whole number, depending on the rounding convention used. For example, if the actual area is 100 cm2, it could be rounded to either 100 cm2 or 1000 cm2, depending on the rounding convention used.
- Volume: The volume would be rounded to the nearest tenth or whole number, similar to the area. For example, if the actual volume is 0.20 cm3, it could be rounded to either 0.2 cm3 or 0.3 cm3.
- Thickness: The thickness would also be rounded to the nearest tenth or whole number, depending on the rounding convention used. For example, if the actual thickness is 0.002 cm, it could be rounded to either 0.002 cm or 0.01 cm.
This crude method would not be suitable for determining the thickness of an oil spill accurately. To determine the thickness of an oil spill, more precise measurements and equipment would be needed, such as specialized tools to measure the thickness of a liquid layer.
To find the thickness of molecules using the given slope equation, the slope (49.4) represents the change in thickness (y) per unit change in x (which is not given). The slope indicates how the thickness of the molecules changes with respect to another variable or factor (x).
In the case of the oil slick in the swimming pool, the problem states that the density is not needed to calculate the answer. Therefore, to find the thickness of the resulting oil slick, we can directly use the volume of the oil (1.06 quarts or 1000 cm3), divide it by the area of the pool (25.0 m * 30.0 m = 750 m2), and convert the units to give the thickness in cm.
Using exponential notation with significant figures, the calculation would be as follows:
Thickness = Volume / Area
= (1000 cm3) / (750 m^2)
= (1000 cm3) / (750 * 10000 cm2)
= (1000 cm3) / (750 * 10000 * 100 cm2)
= 0.0001333 cm (rounded to 4 significant figures)
Therefore, the resulting oil slick would have a thickness of approximately 0.0001333 cm. This method can be used to estimate the thickness of any given substance, such as oil slicks or other fluids, as long as the necessary measurements and conversions are made accurately.
If you had used a very crude balance that allowed only one significant figure, it would affect the results for area, volume, and thickness. Let's look at each one:
1. Area: The area is calculated by dividing the volume by the thickness. Since the volume and thickness values are given with three significant figures (e.g., 100 cm2 and 0.002 cm), rounding them to one significant figure would give us 100 cm2 and 0.002 cm. Thus, the area calculation would be affected.
2. Volume: The volume is given in cubic centimeters (cm3), and rounding it to one significant figure would result in 0.2 cm3, 0.3 cm3, 0.2 cm3, and 0.4 cm3 for the respective values. Therefore, it would affect the volume calculation as well.
3. Thickness: The thickness is given in centimeters (cm), and rounding it to one significant figure would result in 0.002 cm, 0.002 cm, 0.02 cm, and 0.002 cm for the respective values. Hence, the thickness calculation would be affected.
Regarding determining the thickness of an oil spill, this crude method may not be reliable. To determine the thickness accurately, additional information would be needed, such as the area covered by the spill and the volume of the oil. Simply having the area, volume, and thickness values as given in the table would not be sufficient to determine the thickness of the oil spill.
Moving on to the second question, the slope of the equation y = 49.4x - 30 is 49.4. In this context, the slope represents the change in the thickness (y) per unit change in x. Therefore, for every unit increase in x, the thickness increases by 49.4 units.
For the third question, we have a quart of oil, which is equivalent to 1000 cm3. The oil is dumped into a swimming pool measuring 25.0 m by 30.0 m. To find the thickness of the resulting oil slick, we need to calculate the volume of the slick.
First, let's convert the measurements to centimeters:
Length = 25.0 m = 25.0 m * 100 cm/m = 2500 cm
Width = 30.0 m = 30.0 m * 100 cm/m = 3000 cm
The area of the pool is calculated by multiplying the length and width:
Area of the pool = Length * Width = 2500 cm * 3000 cm = 7,500,000 cm2
Now, we divide the volume of the oil by the area to find the thickness:
Thickness = Volume/Area = 1000 cm3 / 7,500,000 cm2 ≈ 0.0001333 cm
Therefore, the thickness of the resulting oil slick is approximately 0.0001333 cm.
Regarding the use of this method in finding the size of molecules, this method would not be directly applicable. Determining the size of molecules is a complex process that involves various techniques, such as microscopy, spectroscopy, and crystallography, among others. The method used for finding the thickness of the oil slick in the swimming pool would not provide accurate information about the size of molecules.