math
posted by Sasha .
A ladder 10 ft long rests against a vertical wall. let θ be the angle between the top of the ladder and the wall and let x be the distance from the bottom of the ladder to the wall. If the bottom of the ladder slides away from the wall, how fast does x change with respect to θ when θ = π/3

We know that x=Lsin(θ), where L=length of ladder = 10'.
x(θ)=L sin(θ)
x'(θ)=dx/dθ = L cos(θ)
Calculate x'(π/3).
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