Calculate the mass percent composition of iron for the second one of these iron ores.
fe2o3
fe3o4
%Fe = (3*atomic mass Fe/molar mass Fe3O4)*100 = ??
To calculate the mass percent composition of iron in a compound, you need to determine the molar mass of iron and the molar mass of the whole compound.
1. Start by finding the molar mass of iron (Fe) on the periodic table. It is approximately 55.845 grams/mol.
2. For the compound Fe2O3, determine the molar mass by multiplying the molar mass of iron by the subscript 2, and the molar mass of oxygen (O) by the subscript 3. Add these values together.
Molar mass of Fe2O3 = (2 x molar mass of Fe) + (3 x molar mass of O)
= (2 x 55.845) + (3 x 16.00)
= 111.69 + 48.00
= 159.69 grams/mol
3. To find the mass percent composition of iron in Fe2O3, divide the molar mass of iron by the molar mass of Fe2O3 and multiply by 100.
Mass percent composition of iron = (molar mass of Fe / molar mass of Fe2O3) x 100
= (2 x 55.845 / 159.69) x 100
= 111.69 / 159.69 x 100
≈ 69.93%
So, the mass percent composition of iron in Fe2O3 is approximately 69.93%.
Now, let's calculate the mass percent composition of iron in Fe3O4.
1. Using the same molar mass of iron (Fe) as before (55.845 grams/mol), we calculate the molar mass of Fe3O4 by multiplying the molar mass of iron by the subscript 3, and the molar mass of oxygen (O) by the subscript 4. Add these values together.
Molar mass of Fe3O4 = (3 x molar mass of Fe) + (4 x molar mass of O)
= (3 x 55.845) + (4 x 16.00)
= 167.535 + 64.00
= 231.535 grams/mol
2. To find the mass percent composition of iron in Fe3O4, divide the molar mass of iron by the molar mass of Fe3O4 and multiply by 100.
Mass percent composition of iron = (molar mass of Fe / molar mass of Fe3O4) x 100
= (3 x 55.845 / 231.535) x 100
= 167.535 / 231.535 x 100
≈ 72.36%
Therefore, the mass percent composition of iron in Fe3O4 is approximately 72.36%.