Given an allele frequency of o.91 for a hypothetical red allele (bead), the percentage of blue alleles residing in the heterozygotes would be?
a) 89% b) 90% c) 91% d) 92% e)93%
i don't even know how to approach this question
To solve this question, we need to understand the concept of allele frequencies and heterozygotes.
Allele frequency refers to the proportion of a specific allele within a population. In this case, the allele frequency for the red allele is given as 0.91.
Heterozygotes, also known as individuals with two different alleles for a particular gene, have one copy of each allele. In this scenario, we want to determine the percentage of heterozygotes that possess the blue allele.
To find the percentage of blue alleles residing in the heterozygotes, we need to subtract the frequency of the red allele from 1, as the sum of allele frequencies must be equal to 1 for a diploid organism. The remaining proportion would represent the blue allele frequency.
1 - 0.91 = 0.09
So, the percentage of blue alleles is 0.09 or 9%.
Now we can check which option matches our answer:
a) 89% - Not the same as our calculated percentage
b) 90% - Not the same as our calculated percentage
c) 91% - Not the same as our calculated percentage
d) 92% - Not the same as our calculated percentage
e) 93% - Not the same as our calculated percentage
Therefore, none of the options matches our calculated percentage of blue alleles.