A golf club contacts a ball for 0.15 s at angle to horizontal and the ball strikes ground distance from fairway. Initial speed 25 m/s and angle of projection is 15 degrees

Calculate time between
1.ball leaving club and when it first touches ground
2.range of ball down fairway

Please direct me where to even start or show me some of the steps please

http://www.jiskha.com/display.cgi?id=1286217809

I have a question? What does hf = hi+Vivertical stand for? I haven't seen hf or hi or Vivertical yet in class-I just started a few weeks ago.

Thank you for the direction- -Sorry I didn't check what someone else asked-I guess I should have.

To solve the problem, we can break it down into two parts:

1. Finding the time the ball is in the air
2. Calculating the range or horizontal distance traveled by the ball.

Let's start by finding the time the ball spends in the air.

Step 1: Break the initial velocity into horizontal and vertical components.
The initial velocity (v) of the ball is given as 25 m/s at an angle of 15 degrees to the horizontal. We can break this down into horizontal (v_x) and vertical (v_y) components:
v_x = v * cos(theta)
v_y = v * sin(theta)

Step 2: Calculate the time of flight (t_flight) or time the ball is in the air.
To calculate the time the ball is in the air, we can use the vertical component of the velocity and the acceleration due to gravity (g = 9.8 m/s^2):
We know that the time of flight can be found using the formula:
t_flight = (2 * v_y) / g

Step 3: Calculate the horizontal distance traveled by the ball (range or distance from the fairway).
To calculate the range, we need to determine the horizontal component of the displacement (x) covered by the ball during the time of flight.
We can use the formula:
range (x) = v_x * t_flight

Now, let's solve for the values:

Step 1:
v_x = 25 m/s * cos(15 degrees) ≈ 24.085 m/s
v_y = 25 m/s * sin(15 degrees) ≈ 6.419 m/s

Step 2:
t_flight = (2 * v_y) / g = (2 * 6.419 m/s) / 9.8 m/s^2 ≈ 1.31 s

Step 3:
range (x) = v_x * t_flight = 24.085 m/s * 1.31 s ≈ 31.6 m

Now, let's summarize the answers to the questions:

1. Time between ball leaving the club and when it first touches the ground:
The time of flight is approximately 1.31 seconds.

2. Range of the ball down the fairway:
The range or horizontal distance traveled by the ball is approximately 31.6 meters.

Please note that these calculations assume no air resistance and a level fairway.