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If the initial pressure of H2S(g) is 7.404 atm, calculate the % decomposition of H2S(g) when the reaction comes to equilibrium according to the balanced equation. The value of Kp at 1132 °C is 0.0265. The initial pressure of the reaction products is 0 atm.

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    Is the equation given as
    H2S --> H2 + S

    Set up ICE chart and substitute into Kp.
    Initial:
    pH2 = 0
    pS = 0
    pH2S = 7.404

    change:
    S = +x
    H2 = +x
    H2S = -x

    equilibrium:
    S = x
    H2 = x
    H2S = 7.404-x

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