Calculus: Application of Integration
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Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating rectangle and label ts height and width. Then find the area of the region.
y=x^2
y^2=x

It is easy to see that the two curves intersect at (0,0) and (1,1)
I will integrate with respect to x
area = [integral] (x^(1/2)  x^2) dx from 0 to 1
= [(2/3)x^(3/2)  (1/3)x^3] from 0 to 1
= 2/3  1/3  0
= 1/3
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