chem
posted by lisa .
Po218 is an alpha emitter with a halflife of 3.0 minutes. If a sample contains 69 mg of Po218, how many alpha emissions would occur in 6.0 minutes?
the answer has to be _________a emmisions (which I have no idea what it means)
and I use a chart thing with amount, #HL, and time passed as the collums.

I would do something like this.
(Number of half lives = 6/3 = 2.)
2^{n}n = 2^{6/3} = 2^{2} = 4 and
69 mg/4 = 17.25 Po atoms remain. The mass that emitted must be 69mg17.25mg = 51.75 mg or 0.05175 grams.
I would change that to moles (moles = grams/molar mass) and remember that 1 mole of atoms contains 6.022 x 10^23 atoms.
So moles x 6.022 x 10^23 = ??number of alpha emissions.
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