write a balanced chemical equation for the reaction that occurs when aqueous solutions of sodium chloride and sodium iodate are mixed
Why do you think there is a reaction?
NaCl(aq) + NaIO3(aq) ==> 2Na^+(aq) + Cl^-(aq) + IO3^-(aq)
To write a balanced chemical equation for the reaction that occurs when aqueous solutions of sodium chloride (NaCl) and sodium iodate (NaIO3) are mixed, we need to determine the chemical formulas of the resulting products.
The reaction between sodium chloride and sodium iodate can be represented by the following equation:
2 NaCl + NaIO3 → 2 NaI + Cl2 + 2 NaOH
Let's break down the equation and explain how to balance it:
1. Start by identifying and listing the reactants and products involved in the reaction:
Reactants: Sodium chloride (NaCl) and sodium iodate (NaIO3)
Products: Sodium iodide (NaI), chlorine gas (Cl2), and sodium hydroxide (NaOH)
2. Write the unbalanced equation, making sure to correctly represent the reactants and products:
NaCl + NaIO3 → NaI + Cl2 + NaOH
3. Balance the equation by adjusting the coefficients of the compounds to have an equal number of atoms on both sides of the equation:
2 NaCl + NaIO3 → 2 NaI + Cl2 + 2 NaOH
In the balanced equation, there are now two molecules of sodium chloride reacting with one molecule of sodium iodate to produce two molecules of sodium iodide, one molecule of chlorine gas, and two molecules of sodium hydroxide. This balanced equation ensures that the law of conservation of mass is upheld, with the same number and types of atoms on both sides of the equation.