Calculate how many moles of NH_3 form when each quantity of reactant completely reacts 3N_2H_4(l)-->NH_3(g)+N_2(g)
-2.5mol N_2H_4
-4.05mol N_2H_4
-65.8g N_2H_4
-4.52kg N_2H_4
To calculate the number of moles of NH₃ formed when each quantity of reactant completely reacts in the given balanced chemical equation (3N₂H₄(l) → NH₃(g) + N₂(g)), you need to follow these steps:
Step 1: Determine the molar ratio between N₂H₄ and NH₃ in the balanced equation.
From the equation, you can see that the coefficient of N₂H₄ is 3, while the coefficient of NH₃ is also 3. This means that for every 3 moles of N₂H₄ used, 3 moles of NH₃ are produced.
Step 2: Convert the given units to moles if necessary.
If the given quantities are already in moles, you can move on to Step 3. Otherwise, you need to convert the given quantities to moles.
- For 2.5 mol of N₂H₄:
Since the molar ratio is 3:3, it means that 2.5 mol of N₂H₄ will produce 2.5 mol of NH₃.
- For 4.05 mol of N₂H₄:
Using the molar ratio mentioned earlier, 4.05 mol of N₂H₄ will give you 4.05 mol of NH₃.
- For 65.8 g of N₂H₄:
First, you need to calculate the number of moles of N₂H₄. The molar mass of N₂H₄ is 32.05 g/mol.
Number of moles = mass / molar mass
Number of moles = 65.8 g / 32.05 g/mol = 2.0530 mol
Using the molar ratio, 2.0530 mol of N₂H₄ will give you 2.0530 mol of NH₃.
- For 4.52 kg of N₂H₄:
First, convert the mass from kg to g.
4.52 kg = 4520 g
Next, calculate the number of moles of N₂H₄.
Number of moles = mass / molar mass
Number of moles = 4520 g / 32.05 g/mol = 141.0804 mol
Using the molar ratio, 141.0804 mol of N₂H₄ will give you 141.0804 mol of NH₃.
Step 3: Calculate the number of moles of NH₃ formed.
Summarizing the results from the previous steps:
- For 2.5 mol of N₂H₄, 2.5 mol of NH₃ is formed.
- For 4.05 mol of N₂H₄, 4.05 mol of NH₃ is formed.
- For 65.8 g of N₂H₄, 2.0530 mol of NH₃ is formed.
- For 4.52 kg of N₂H₄, 141.0804 mol of NH₃ is formed.