# Chemistry Help

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Calculate how many moles of NH_3 form when each quantity of reactant completely reacts 3N_2H_4(l)-->NH_3(g)+N_2(g)

-2.5mol N_2H_4

-4.05mol N_2H_4

-65.8g N_2H_4

-4.52kg N_2H_4

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