A bag cntains 100 bolts nd 300 nuts 50% f each hv been rusted 1 item z chosen at random.
Find da probability dat chosen item z rusted or a bolt.
To find the probability that the chosen item is either rusted or a bolt, we need to find the number of items that satisfy both conditions.
First, let's calculate the number of rusted bolts:
The bag contains 100 bolts, and 50% of them are rusted, so the number of rusted bolts is 100 * 0.50 = 50.
Next, let's calculate the number of non-rusted bolts:
Since 50% of the bolts are rusted, the remaining 50% are non-rusted. So the number of non-rusted bolts is also 100 * 0.50 = 50.
Now let's calculate the number of nuts that are rusted:
The bag contains 300 nuts, and 50% of them are rusted, so the number of rusted nuts is 300 * 0.50 = 150.
Lastly, let's calculate the total number of items in the bag:
The bag contains 100 bolts and 300 nuts, so the total number of items is 100 + 300 = 400.
To find the probability that the chosen item is either rusted or a bolt, we need to add the number of rusted bolts (50), non-rusted bolts (50), and rusted nuts (150).
The total number of items that satisfy both conditions is 50 + 50 + 150 = 250.
Therefore, the probability that the chosen item is either rusted or a bolt is 250/400 = 0.625 or 62.5%.