A sample of 9.4 grams of NaOH is dissolved into 693 mL of aqueous 0.250 M NaOH (assume no volume change). This solution is then poured into 2.37 gallons of water. (You may assume that the two volumes can be

added.) What is the concentration of NaOH in the final solution?
Answer in units of M.

To find the concentration of NaOH in the final solution, we need to consider the amount of NaOH and the total volume of the solution.

First, we need to convert the volume of water from gallons to milliliters since the given concentration is in Molarity (moles per liter).

- 1 gallon is approximately equal to 3785.41 milliliters.
- So, 2.37 gallons is equal to 2.37 * 3785.41 milliliters ≈ 8988.9 milliliters.

Next, we calculate the moles of NaOH dissolved in the initial solution:
- Given mass of NaOH = 9.4 grams.
- Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol.
- Moles of NaOH = mass / molar mass = 9.4 g / 40 g/mol = 0.235 mol.

Since the volume of the aqueous NaOH solution doesn't change when mixed with water, the moles of NaOH remain the same.

Next, we need to calculate the total volume of the final solution:
- Volume of aqueous NaOH solution = 693 mL.
- Volume of water = 8988.9 mL.
- Total volume = volume of aqueous NaOH + volume of water = 693 mL + 8988.9 mL = 9681.9 mL.

Finally, we calculate the concentration of NaOH in the final solution:
- Concentration (in Molarity) = moles of NaOH / total volume (in liters).
- Moles of NaOH = 0.235 mol.
- Total volume = 9681.9 mL = 9681.9 mL / 1000 mL/L = 9.6819 L.

Concentration = 0.235 mol / 9.6819 L ≈ 0.0242 M.

So, the concentration of NaOH in the final solution is approximately 0.0242 M.

moles solid NaOH = 9.4 g/molar mass NaOH = ??

moles NaOH solution = M x L = ??
Add to find the sum of the moles. This is the total NaOH dissolved (in moles).
Now convert 2.37 gallons of water to mL and concn NaOH (molarity) = total moles/L.Post your work if you get stuck.