College Physics
posted by Dan .
A car starts from rest on a curve with a radius of 150 m and accelerates at 1.50 m/s^2. How many revolutions will the car have gone through when the magnitude of its total acceleration is 3.20 m/s^2 ?

College Physics 
bobpursley
total acceleration= sqrt(1.5^2+(v^2/r)^2)
3.2^21.5^2=(v^2/r)^2
solve for v^2/r
then,
angvelocity^2=2*angularacceleration*angulardisplacement
(V^2/r)1/r=2*1.50/r*angulardisplacement
solve for angular displacement, divide by 2PI to get revolutions
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