How much of a 0.25 M NaOH solution is needed to neutralize 100 mL of a 0.15 M HCl solution? The units are mL

To determine how much of the 0.25 M NaOH solution is needed to neutralize 100 mL of a 0.15 M HCl solution, you can use the following steps:

Step 1: Write and balance the chemical equation for the reaction between NaOH and HCl:

NaOH + HCl → NaCl + H2O

Step 2: Determine the molar ratio between NaOH and HCl based on the balanced equation. From the equation, we can see that one mole of NaOH reacts with one mole of HCl.

Step 3: Calculate the number of moles of HCl in the 100 mL of 0.15 M HCl solution.

Moles of HCl = Molarity × Volume (in liters)

Moles of HCl = 0.15 M × 0.1 L
= 0.015 moles

Step 4: Determine the volume of 0.25 M NaOH needed to neutralize the 0.015 moles of HCl.

Volume of NaOH = Moles of HCl ÷ Molarity of NaOH

Volume of NaOH = 0.015 moles ÷ 0.25 M
= 0.06 liters or 60 mL

Therefore, you would need 60 mL of the 0.25 M NaOH solution to neutralize 100 mL of the 0.15 M HCl solution.

To determine how much of a 0.25 M NaOH solution is needed to neutralize 100 mL of a 0.15 M HCl solution, you can use the concept of stoichiometry.

The balanced chemical equation for the reaction between NaOH and HCl is:

NaOH + HCl -> NaCl + H2O

From the equation, it can be determined that 1 mole of NaOH reacts with 1 mole of HCl on a one-to-one basis.

First, calculate the number of moles of HCl present in the 0.15 M solution using the formula:

moles = concentration (M) * volume (L)

Since the volume is given in mL, you need to convert it to liters:

volume (L) = volume (mL) / 1000

moles of HCl = 0.15 M * (100 mL / 1000) = 0.015 moles

Since the reaction is one-to-one, this means that 0.015 moles of NaOH are needed to neutralize 0.015 moles of HCl.

Now, calculate the volume of the 0.25 M NaOH solution needed to obtain 0.015 moles. Rearrange the formula above:

volume (L) = moles / concentration (M)

volume (L) = 0.015 moles / 0.25 M = 0.06 L

Finally, convert the volume from liters to milliliters:

volume (mL) = volume (L) * 1000 = 0.06 L * 1000 = 60 mL

Therefore, 60 mL of the 0.25 M NaOH solution is needed to neutralize 100 mL of the 0.15 M HCl solution.

Since the reaction is 1:1---

NaOH + HCl ==> NaCl + H2O

you may use the simple formula of
mL x M = mL x M.