The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8. I use the change of base formula and got log6/log2 * log8/log6 Which become log6/log2 * log2()^3/ log 6 I'm stuck here thanks.
Given log2=0.3010, log3=0.4771, log5=0.6690, and log7=0.8451... Find a.) log8 b) log5/7 c.) log1.5 d.) log3/14 e) log12 I didn't know how to do b, c, and d. I also don't know if log 12 is right. Answer: a.) 0.903 b.)?
Assume that x, y, and b are positive numbers. Use the properties of logarithms to write the expression logb ^8xy in terms of the logarithms of x and y. a. logb^8 + logb x + logb^y b. logb^8+logbx c. logb^8+logby d. logb^8 + log8 x …
Logarithms 3^x-2=18 Work log(3^x-2)=log18 (x-2)log3=log18 xlog3-2log3=log18 x=log3/(log9-log18) e^3x+1=10 lne^3x+1=ln10 3x+1=ln10 I'm stuck here 8^x=5^2x-1 xlog8=(2x-1)log5 xlog8=2xlog5-log5 x=log10/(log5-log8) Are these right?