using the values for heat of fusion, specific heat of water, or heat of vaporization, calculate the amount of heat energy.

Calories needed to warm 20.0g of water at 15 degrees Celsius to 72 degrees Celsius (one step) Show work please

q = mass water x specific heat water x (Tfinal-Tinitial). Substitute and solve for q.

75

To calculate the amount of heat energy needed to warm water from one temperature to another, you can use the equation:

Q = m * c * ΔT,

where:
Q is the amount of heat energy (in calories),
m is the mass of water (in grams),
c is the specific heat of water (in calories/gram °C),
ΔT is the change in temperature (in °C).

Given values:
m = 20.0g
c = 1.00 cal/g °C (specific heat of water)
ΔT = 72°C - 15°C = 57°C

Now, plug in the values into the equation:

Q = 20.0g * 1.00 cal/g °C * 57°C

Calculating this, we get:

Q = 1,140 calories

Therefore, the amount of heat energy needed to warm 20.0g of water from 15°C to 72°C is 1,140 calories.