# Chemistry

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Calculate the volume of Carbon dioxide gas generated when 40.0 g of sodium carbonate reacts with hydrocholric acid according to the following reaction. The gas is to be collected at STP

Na2CO3 + HCL-----> NaCL +H2O + CO2(g)

• Chemistry -

Balance the eqn
Na2CO3 + 2HCl -> 2NaCl +H20 + CO2

From the balanced eqn you can see that one mole of CO2 is produced.

Then at stp 1 mole of gas takes up 24 litres (I think, check this on google) therefore v= 24 litres.
:)

• Chemistry -

Convert 40 g Na2CO3 to moles. moles = grams/molar mass. Since 1 mole Na2CO3 produces 1 mole CO2, moles Na2CO3 above will contribute that many moles CO2 @ STP. Remember 1 mole CO2 @ STP occupies 22.4 L.

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