Calculate the volume of 1.80 M \rm Na_3PO_4 in milliliters that contains 6.00 g of solute.
I don't know what \rm means.
To calculate the volume of a solution, we need to use the concentration and amount of solute. In this case, we are given the concentration of the solution (1.80 M) and the mass of the solute (6.00 g).
First, we need to convert the mass of the solute from grams to moles. We can do this by dividing the mass by the molar mass of Na3PO4.
The molar mass of Na3PO4 can be calculated by multiplying the atomic masses of each element by the number of atoms in the chemical formula:
Na: 22.99 g/mol
P: 30.97 g/mol
O: 16.00 g/mol (x4)
Molar mass of Na3PO4 = (22.99 g/mol * 3) + 30.97 g/mol + (16.00 g/mol * 4) = 163.94 g/mol
Now, we can calculate the number of moles of solute:
Number of moles = mass of solute / molar mass
Number of moles = 6.00 g / 163.94 g/mol
Next, we need to use the concentration and the number of moles to calculate the volume of the solution.
Concentration of the solution (1.80 M) means that there are 1.80 moles of Na3PO4 in 1 liter (1000 ml) of solution.
We can set up a proportion to find the volume of the solution:
Concentration (M) = moles / volume (L)
1.80 M = (number of moles) / (volume in liters)
Solving for volume in liters:
Volume (L) = (number of moles) / concentration (M)
Volume (L) = (6.00 g / 163.94 g/mol) / 1.80 M
Finally, we need to convert the volume from liters to milliliters.
1 L = 1000 ml
Volume (mL) = Volume (L) * 1000
Volume (mL) = [(6.00 g / 163.94 g/mol) / 1.80 M] * 1000
Evaluate this expression to find the volume of the solution in milliliters.