Find the intercepts of the equation y=2x-1 by plotting points.
To plot this would I just plot 2,0 and then go down 1?
To find the x-intercept, let y=0 and solve for x.
Therefore,
0=2x-1 ---> x=1/2
To find the y-intercept, let x=0 instead.
y=2(0)-1 ---> y=-1
From here, you plot the points (1/2,0) and (0,-1) on the graph.
Thank You!
To find the intercepts of the equation y = 2x - 1, you can plot points or use algebraic methods.
By plotting points, you can find the x and y coordinates where the graph intersects the axes. To find the x-intercept, set y = 0 and solve for x:
0 = 2x - 1
2x = 1
x = 1/2
So the x-coordinate of the x-intercept is 1/2. To plot this point, draw a dot at (1/2, 0) on the x-axis.
To find the y-intercept, set x = 0 and solve for y:
y = 2(0) - 1
y = -1
The y-coordinate of the y-intercept is -1. To plot this point, draw a dot at (0, -1) on the y-axis.
Now, you have two points: the x-intercept at (1/2, 0) and the y-intercept at (0, -1). You can connect these two points with a straight line to represent the graph of the equation y = 2x - 1.