statistics
posted by Anonymous .
Suppose that the heights of adult men in the United States are normally distributed with a mean of inches and a standard deviation of inches. What proportion of the adult men in United States are more than feet tall? (Hint: feet inches.) Round your answer to at least four decimal places.

find the zscore:
z=(xmu)/sigma
where mu= mean and sigma=standard deviation
after you find the zscore, you need to look at the zscore chart for the proportion
http://www.thebeststatistics.info/sta/table_zvals.html
Respond to this Question
Similar Questions

statistics
Suppose that the heights of adult men in the United States are normally distributed with a mean of inches and a standard deviation of inches. What proportion of the adult men in United States are more than feet tall? 
statistics
It is well known that the heights of individual American men are normally distributed with mean 70 inches and standard deviation 2.8 inches. The Central Limit Theorem states that if n men are randomly chosen, then their average height … 
Statistic
Heights of adult men have a mean of 69.0 inches and a standard deviation of 2.8 inches. Approximately what percentage of adult men have a height between 66.2 and 77.4 inches? 
Statistics
The distribution of heights of adult American men is approximately normal with a mean of 68 inches and a standard deviation of 2 inches. What percent of mean are at least 72 inches tall? 
Calculus
According to the National Health Survey, the heights of adult males in the United States are normally distributed with mean 69.0 inches and standard deviation 2.8 inches. A. What is the probability that an adult male chosen at random … 
MBA
1 The height of adult women in the United States is normally distributed with mean 64.5 inches and standard deviation 2.4 inches. Find the probability that a randomly chosen woman is (a) Less than 63 inches tall (b) Less than 70 inches … 
Statistics
It is estimated that heights of adult men are normally distributed with a mean of 70 inches and a standard deviation of 3.5. In one state, the law requires a person to be 68 inches or taller to become a fire fighter. (a) What proportion … 
Statistics
Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. What percent of men are over 6 feet tall? 
Math
Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. What percent of men are over 6 feet tall? 
Statistics Please help me :(
I have no idea where to even start. Suppose heights of men are normally distributed with a mean 69.0 inches and standard deviation 2.8 inches. How many of a group of 1000 men would you expect to be between 70 and 72 inches tall?