two-thirds of the atoms that make up H2S are hydrogen. What percentage of the weight of hydrogen sulfide is the weight of the two hydrogens?
(2*atomic mass H/molar mass H2S)*100 = ??
To find the percentage of the weight of hydrogen sulfide that is contributed by the weight of the two hydrogens, we first need to know the atomic masses of hydrogen and sulfur.
The atomic mass of hydrogen (H) is approximately 1 gram/mol, and the atomic mass of sulfur (S) is approximately 32 grams/mol.
Given that two-thirds of the atoms in H2S are hydrogen, we can calculate the weight of the two hydrogens as follows:
Weight of two hydrogens = (2/3) × (2 × atomic mass of hydrogen)
Substituting the values:
Weight of two hydrogens = (2/3) × (2 × 1) = (2/3) × 2 = 4/3 grams
Now, to calculate the percentage of the weight of hydrogen sulfide contributed by the weight of the two hydrogens, we divide the weight of the two hydrogens by the molecular weight of H2S and multiply by 100:
Percentage = (Weight of two hydrogens / Molecular weight of H2S) × 100
Molecular weight of H2S = (atomic mass of hydrogen × 2) + atomic mass of sulfur = (1 × 2) + 32 = 2 + 32 = 34 grams/mol
Substituting the values:
Percentage = (4/3 grams / 34 grams) × 100
Simplifying the expression:
Percentage = (4/3) × (100/34) ≈ 11.8%
Therefore, approximately 11.8% of the weight of hydrogen sulfide is the weight of the two hydrogens.