calculus

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Find the point on the curve y=1 x2+14 x such that the tangent line to the curve is parallel to 2 x + 10 y = 23

  • calculus -

    2x+10y=23 (is what im guessing since the problem breaks awkwardly there)

    y=-1/5x+23/10 (slope intercept form)

    derivative of y=x^2+14x (im guessing since it looks like you expressed it wrong)

    y'=2x+14

    I'll leave it up to you at that point.

  • calculus -

    Yes. Sorry.

    I did get it up to the derivative of y' = 2x + 14 by using the
    f'(x) = [f(x+h) - f(x)] / h
    formula.

    and did simplify the other equation into the slope-intercept form.

    but do I just plug the derivative into the 'slope-intercept' equation?

    because isn't y' = 2x+14 the slope of the tangent.

    I guess I'm mostly confused because I need to find a point parallel to that second equation and for the point to be parallel, they must have the same slope.
    yet the derivative gave me a different slope?

  • calculus -

    For slope intercept form,
    y=mx+b
    m is the slope.
    You need to find the value of x for which
    f'(x)=m, i.e. tangent parallel to y=mx+b.

  • calculus -

    A slope can't be an equation. It's a number, and your solving for x so that the equation equals the slope of the line.

    Also your teacher taught you the long way of doing a derivative, if the "Power Rule" for derivatives never comes up in class you're better off looking it up yourself.

  • calculus -

    I'm sorry. For the life of me, I just can't figure out this problem.

    Okay, so if the slope can't be an equation, can i solve for x by setting y' equal to zero?

    or do you mean
    2x + 14 = (-1/5) x + (23/10)

    I tried both ways I just listed, and they turned out wrong, so I'm still lost.

    He did teach us the shortcut during my last class. It was just a force of habit to do it the long way.

    Thank you so much for helping me.

  • calculus -

    I've also just tried:
    -1/5 = 2x + 14
    x = -.568

    and plugged that into the 'parallel' equation to solve for y.
    y= 2.4136

    but that still didn't work out.

  • calculus -

    what's the slope of the line?

    set 2x+14 equal to that and solve.

    (hint:slope intercept form y=mx+b)

    sorry if i sound like a twat but trust me that you'll remember things better if you figure them out yourself.

  • calculus -

    how on earth did you get x=-.568

    the equation is right you just solved it wrong.

  • calculus -

    Okay. My bad.
    I'm sorry all, I apparently can't do basic math.


    Thank you everyone for helping me.
    I really appreciated it.

  • calculus -

    x=-7.1

  • calculus -

    Alright. One last question.

    So I'm wondering if my online homework answer is wrong, because I have x and I've plugged x back into the y = (-1/5)x + (23/10)
    and I've solved for y.
    y = 3.72

    Now please tell me if I'm just making a fool of myself again and am incorrectly solving an algebraic equation or is it wrong, because it won't accept 3.72 as the y, but accepts -7.1 as the x.

  • calculus -

    you don't plug it into the equation of the line.

    what you are trying to do is to get the derivative equal to the slope of the line y=-1/5x+23/10

    y=mx+b
    so the slope, m=(-1/5)

    therefore -1/5=2x+14

    where x=(-7.1)

    check your solution
    y=2(-7.1)+14=-.2 (or -1/5)

  • calculus -

    my oh my oh my !!!
    why did you not follow MathMate's idea?

    y' = 2x + 14, that is your slope at any point (x,y)
    the slope of the given straight line is -1/5
    so 2x + 14 = -1/5
    x = 7.1 You had that!
    then y = (7.1)^2 + 14(7.1) = 149.81

    so the point of contact is (7.1, 149.81)

    since the new line is parallel to the old, it must have the same x and y terms, so

    2x + 10y = c
    plug in the point
    2(7.1) + 10(149.81) = c = 1512.3

    equation:
    2x + 10y = 1512.3

  • calculus -

    derivative is a slope. so y'=..... is not the same as y=.....

    think of y' as m, a slope as well but tangent to graph.

  • calculus -

    >Reiny

    spoon fed the answer right there, so yeah never plug it in to the equation of the line.

  • calculus -

    Wow thank you guys all so much.

    I'm dreading a whole semester of calculus.
    (stats was so much easier)

    Thanks especially for explaining everything, so now I understand it.

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