Please identify the net ionic equation for Na3PO4 +ZnSO4=Zn3(PO4)2+ Na2SO4
To determine the net ionic equation for the given reaction, we first need to write the balanced equation. Then, we can identify the spectator ions and omit them from the equation, resulting in the net ionic equation.
The balanced equation for the reaction between sodium phosphate (Na3PO4) and zinc sulfate (ZnSO4) is:
3 Na3PO4 + ZnSO4 → Zn3(PO4)2 + 3 Na2SO4
Now, let's determine the spectator ions.
The ions that remain unchanged during the reaction and appear on both sides of the equation are spectator ions. In this reaction, the sodium ions (Na+) and sulfate ions (SO4^2-) are spectator ions because they are present on both sides of the equation.
Therefore, we can omit the spectator ions to write the net ionic equation:
3 Na+ + 3 PO4^3- + Zn^2+ → Zn3(PO4)2
So, the net ionic equation for the given reaction is 3 Na+ + 3 PO4^3- + Zn^2+ → Zn3(PO4)2.
To determine the net ionic equation for the reaction between Na3PO4 (sodium phosphate) and ZnSO4 (zinc sulfate) to form Zn3(PO4)2 (zinc phosphate) and Na2SO4 (sodium sulfate), we first need to write the balanced chemical equation:
2 Na3PO4 + 3 ZnSO4 → Zn3(PO4)2 + 3Na2SO4
Now, we can write the net ionic equation by removing the spectator ions that do not participate in the reaction:
2 PO4³⁻ + 3 Zn²⁺ → Zn3(PO4)2
The net ionic equation, therefore, is:
2 PO4³⁻ + 3 Zn²⁺ → Zn3(PO4)2
Look for the precipitate, gas, or weak electrolyte. In this case it's the zinc phosphate that is insoluble.
PO4^-3(aq) + Zn^+2(aq) ==>Zn3(PO4)2(s)
Here is a site that gives the solubility rules.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html