can I trouble any one with this que
stion. I got jello brain right now.
7-(-1)/3(2)-9/(-3)
Of course! I can help you with that.
To solve the expression 7-(-1)/3(2)-9/(-3), we need to follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction).
Let's break it down step by step:
Step 1: Simplify the division inside the parentheses: -1 divided by 3. This equals to -1/3.
Now our expression becomes: 7 - (-1/3)(2) - 9/(-3).
Step 2: Simplify the multiplication inside the parentheses: (-1/3)(2). Multiply -1/3 by 2, which gives us -2/3.
Now our expression becomes: 7 - (-2/3) - 9/(-3).
Step 3: Simplify the division outside the parentheses: 9 divided by -3. This equals to -3.
Now our expression becomes: 7 - (-2/3) - (-3).
Step 4: Evaluate the subtraction:
7 - (-2/3) = 7 + 2/3. To add fractions with different denominators, we need a common denominator. The common denominator of 3 and 1 is 3. So, we can rewrite 7 as 21/3:
(21/3) + (2/3) = 23/3.
Now our expression becomes: 23/3 - (-3).
Step 5: Simplify the subtraction:
23/3 - (-3) = 23/3 + 3. To add a whole number to a fraction, we need to convert the whole number to a fraction with the same denominator as the fraction. So, we can write 3 as 9/3:
23/3 + 9/3 = 32/3.
Therefore, the simplified result of the expression 7-(-1)/3(2)-9/(-3) is 32/3.